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Get submenus working in secondary menu

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For #2
This commit is contained in:
jderose9
2017-02-24 22:02:31 -05:00
parent b0bf330219
commit b86e84d389
1 changed files with 13 additions and 3 deletions
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16
secondaryMenu.js
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@@ -133,8 +133,8 @@ _redisplay: function() {
let appMenu = this._source.app.menu;
if(appMenu) {
this._appendSeparator();
this._remoteMenu = new RemoteMenu.RemoteMenu(this._source.actor, this._source.app.menu, this._source.app.action_group);
let appMenuItems = this._remoteMenu._getMenuItems();
let remoteMenu = new RemoteMenu.RemoteMenu(this._source.actor, this._source.app.menu, this._source.app.action_group);
let appMenuItems = remoteMenu._getMenuItems();
for(let appMenuIdx in appMenuItems){
let menuItem = appMenuItems[appMenuIdx];
let labelText = menuItem.actor.label_actor.text;
@@ -170,7 +170,17 @@ _redisplay: function() {
}));
menuItem.actor.get_parent().remove_child(menuItem.actor);
this.addMenuItem(menuItem);
if(menuItem instanceof PopupMenu.PopupSubMenuMenuItem) {
let newSubMenuMenuItem = new PopupMenu.PopupSubMenuMenuItem(labelText);
let appSubMenuItems = menuItem.menu._getMenuItems();
for(let appSubMenuIdx in appSubMenuItems){
let subMenuItem = appSubMenuItems[appSubMenuIdx];
subMenuItem.actor.get_parent().remove_child(subMenuItem.actor);
newSubMenuMenuItem.menu.addMenuItem(subMenuItem);
}
this.addMenuItem(newSubMenuMenuItem);
} else
this.addMenuItem(menuItem);
}
}