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pam-util: make pam_debug_syslog_errno() returns pam error

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Currently, the result of pam_debug_syslog_errno() is unused, hence this
does not change anything and may be slightly redundant. But let's follow
our usual coding style.
This commit is contained in:
Yu Watanabe
2025-11-21 09:21:25 +09:00
parent 82f2eb73b1
commit 7214aa9a2c
1 changed files with 4 additions and 2 deletions
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6
src/shared/pam-util.h
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@@ -47,8 +47,10 @@ int pam_syslog_pam_error(pam_handle_t *handle, int level, int error, const char
/* Call pam_syslog_errno if debug is enabled */
#define pam_debug_syslog_errno(handle, debug, error, fmt, ...) \
({ \
if (debug) \
pam_syslog_errno(handle, LOG_DEBUG, error, fmt, ## __VA_ARGS__); \
int _error = (error); \
debug ? \
pam_syslog_errno(handle, LOG_DEBUG, _error, fmt, ## __VA_ARGS__) : \
errno_to_pam_error(_error); \
})
static inline int pam_log_oom(pam_handle_t *handle) {